⑴ 我的手机丢了,现在换了手机问题电脑上的备份文件是.json要怎么办
你之前是用什么进来行备份的就怎么源恢复回来啊,
我平时都是使用数据线连接电脑和手机,打开USB调试,
使事先安装在电脑里的应用宝PC版识别机型,完成连接,
在页面上点击我的手机选项,打开左边的工具箱,
点击资料备份,选择手机里的数据,选择输出的位置,
点击开始,这样就把手机资料备份在你指定的那个文件夹里,
以后就按照同样的方法在工具箱里点击资料恢复,
找到之前输出的那个位置就可以了。
⑵ android 手机怎样解析json数据
可以用一些开源的java库,就可以把这些json数据直接变为Java对象及数组了,然后用Java处理起来很方便。
常用的处理json的库有gson和json-lib,你网络一下可以下到,网上也有例子
⑶ Android 解析json问题
Android 解析json的方式为:
1、首先,搭建一个服务器的工程:JsonProject这个项目
源代码:
Person.java
package com.json.domain;
public class Person {
private int id;
private String name;
private String address;
public Person() {
super();
}
public Person(int id, String name, String addrss) {
super();
this.id = id;
this.name = name;
this.address = addrss;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getAddress() {
return address;
}
public void setAddress(String address) {
this.address = address;
}
@Override
public String toString() {
return "Person [addrss=" + address + ", id=" + id + ", name=" + name
+ "]";
}
}
JsonService.java
package com.json.service;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import com.json.domain.Person;
public class JsonService {
public JsonService() {
}
public Person getPerson(){
Person person = new Person(1001,"jack","上海黄浦区");
return person;
}
public List<Person> getListPerson(){
List<Person> list = new ArrayList<Person>();
Person person1 = new Person(1001,"jack","上海黄浦区");
Person person2 = new Person(1002,"rose","上海闵行区");
Person person3 = new Person(1003,"mick","上海黄浦区");
list.add(person1);
list.add(person2);
list.add(person3);
return list;
}
public List<String> getListString(){
List<String> list = new ArrayList<String>();
list.add("北京");
list.add("上海");
list.add("湖南");
return list;
}
public List<Map<String,Object>> getListMaps(){
List<Map<String,Object>> list = new ArrayList<Map<String,Object>>();
Map<String,Object> map1 = new HashMap<String, Object>();
Map<String,Object> map2 = new HashMap<String, Object>();
map1.put("id", 1001);
map1.put("name", "jack");
map1.put("address", "北京");
map2.put("id", 1001);
map2.put("name", "rose");
map2.put("address", "上海");
list.add(map1);
list.add(map2);
return list;
}
}
JsonServlet.java
package com.json.servlet;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import com.json.service.JsonService;
import com.json.tools.JsonTools;
public class JsonServlet extends HttpServlet {
private JsonService service;
/**
* Constructor of the object.
*/
public JsonServlet() {
super();
}
/**
* Destruction of the servlet. <br>
*/
public void destroy() {
super.destroy(); // Just puts "destroy" string in log
// Put your code here
}
/**
* The doGet method of the servlet. <br>
*
* This method is called when a form has its tag value method equals to get.
*
* @param request the request send by the client to the server
* @param response the response send by the server to the client
* @throws ServletException if an error occurred
* @throws IOException if an error occurred
*/
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
this.doPost(request, response);
}
/**
* The doPost method of the servlet. <br>
*
* This method is called when a form has its tag value method equals to post.
*
* @param request the request send by the client to the server
* @param response the response send by the server to the client
* @throws ServletException if an error occurred
* @throws IOException if an error occurred
*/
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html;charset=utf-8");
request.setCharacterEncoding("utf-8");
response.setCharacterEncoding("utf-8");
PrintWriter out = response.getWriter();
String jsonString = "";
String action_flag = request.getParameter("action_flag");
if(action_flag.equals("person")){
jsonString = JsonTools.createJsonString("person", service.getPerson());
}else if(action_flag.equals("persons")){
jsonString = JsonTools.createJsonString("persons", service.getListPerson());
}else if(action_flag.equals("listString")){
jsonString = JsonTools.createJsonString("listString", service.getListString());
}else if(action_flag.equals("listMap")){
jsonString = JsonTools.createJsonString("listMap", service.getListMaps());
}
out.println(jsonString);
out.flush();
out.close();
}
/**
* Initialization of the servlet. <br>
*
* @throws ServletException if an error occurs
*/
public void init() throws ServletException {
service = new JsonService();
}
}
2、通过浏览器
访问地址一:http://wulianghuan-pc:8080/JsonProject/servlet/JsonServlet?action_flag=person
输出以下结果:
{"person":{"address":"上海黄浦区","id":1001,"name":"jack"}
访问地址二:http://wulianghuan-pc:8080/JsonProject/servlet/JsonServlet?action_flag=persons
输出以下结果:
{"persons":[{"address":"上海黄浦区","id":1001,"name":"jack"},{"addrss":"上海闵行区","id":1002,"name":"rose"},{"address":"上海黄浦区","id":1003,"name":"mick"}]}
访问地址三:http://wulianghuan-pc:8080/JsonProject/servlet/JsonServlet?action_flag=listString
输出以下结果:
{"persons":["北京","上海","湖南"]}
访问地址四:http://wulianghuan-pc:8080/JsonProject/servlet/JsonServlet?action_flag=listMap
输出以下结果:
{"persons":[{"id":1001,"address":"北京","name":"jack"},{"id":1001,"address":"上海","name":"rose"}]}
⑷ 苹果手机如何打开json文件
(1)使用TouchJSon解析方法,将解析得到的内容存放字典中,编码格式为UTF。(2)使用SBJson解析方法,(3)使用IOS5自带解析类NSJSONSerialization方法解析。
json是一个HTTP代理/HTTP监视器/反向代理,使开发人员能够查看其机器和Internet之间的所有HTTP和SSL/HTTPS流量。这包括请求,响应和HTTP标头(包含cookie和缓存信息)Charles是在Mac下常用的网络封包截取工具。
在做移动开发时,我们为了调试与服务器端的网络通讯协议,常常需要截取网络封包来分析。通过将自己设置成系统的网络访问代理服务器,使得所有的网络访问请求都通过它来完成,从而实现了网络封包的截取和分析。除了在做移动开发中调试端口外。
Charles也可以用于分析第三方应用的通讯协议。配合Charles的SSL功能,Charles还可以分析Https协议下载Charles并不是一款免费产品,你需要破解才能使用,建议购买正版软件。这里使用的是文件覆盖的方法。
即:下载新的json文件,并在Charles的安装目录下替换掉它,Windows下替换目录在Charleslib破解的json.jar文件可以在网上搜索下载。
⑸ json是什么格式,在安卓手机上用什么打开
json就是一个字符串,类似树形结构。
只要没加过密,一般的文本编辑器就可以打开。